Derivative of 2^2x w.r.t x is :

22x w.r.t x is :

(A) 2x 22x-1
(B) 22x X ln 2
(C) 4x ln 4
(D) ln 2 . 22x+1

Answer: (B) 22x X ln 2

Solution:

y=2^{2x}

As we know that, if 

y=a^x

 then 

\frac{dy}{dy}=a^x\frac{d}{dx}(x)lna
\frac{dy}{dy}=2^{2x}\frac{d}{dx}(2x)ln2
\frac{dy}{dy}=2^{2x}(2)ln2
\frac{dy}{dy}=2^{2x+1}ln2
\frac{dy}{dy}=ln2.2^{2x+1}